Integrand size = 13, antiderivative size = 30 \[ \int \frac {\left (a+\frac {b}{x}\right )^2}{x^3} \, dx=-\frac {b^2}{4 x^4}-\frac {2 a b}{3 x^3}-\frac {a^2}{2 x^2} \]
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Time = 0.01 (sec) , antiderivative size = 30, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.154, Rules used = {269, 45} \[ \int \frac {\left (a+\frac {b}{x}\right )^2}{x^3} \, dx=-\frac {a^2}{2 x^2}-\frac {2 a b}{3 x^3}-\frac {b^2}{4 x^4} \]
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Rule 45
Rule 269
Rubi steps \begin{align*} \text {integral}& = \int \frac {(b+a x)^2}{x^5} \, dx \\ & = \int \left (\frac {b^2}{x^5}+\frac {2 a b}{x^4}+\frac {a^2}{x^3}\right ) \, dx \\ & = -\frac {b^2}{4 x^4}-\frac {2 a b}{3 x^3}-\frac {a^2}{2 x^2} \\ \end{align*}
Time = 0.00 (sec) , antiderivative size = 30, normalized size of antiderivative = 1.00 \[ \int \frac {\left (a+\frac {b}{x}\right )^2}{x^3} \, dx=-\frac {b^2}{4 x^4}-\frac {2 a b}{3 x^3}-\frac {a^2}{2 x^2} \]
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Time = 0.02 (sec) , antiderivative size = 24, normalized size of antiderivative = 0.80
method | result | size |
norman | \(\frac {-\frac {1}{2} a^{2} x^{2}-\frac {2}{3} a b x -\frac {1}{4} b^{2}}{x^{4}}\) | \(24\) |
risch | \(\frac {-\frac {1}{2} a^{2} x^{2}-\frac {2}{3} a b x -\frac {1}{4} b^{2}}{x^{4}}\) | \(24\) |
gosper | \(-\frac {6 a^{2} x^{2}+8 a b x +3 b^{2}}{12 x^{4}}\) | \(25\) |
default | \(-\frac {b^{2}}{4 x^{4}}-\frac {2 a b}{3 x^{3}}-\frac {a^{2}}{2 x^{2}}\) | \(25\) |
parallelrisch | \(\frac {-6 a^{2} x^{2}-8 a b x -3 b^{2}}{12 x^{4}}\) | \(25\) |
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Time = 0.27 (sec) , antiderivative size = 24, normalized size of antiderivative = 0.80 \[ \int \frac {\left (a+\frac {b}{x}\right )^2}{x^3} \, dx=-\frac {6 \, a^{2} x^{2} + 8 \, a b x + 3 \, b^{2}}{12 \, x^{4}} \]
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Time = 0.08 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.87 \[ \int \frac {\left (a+\frac {b}{x}\right )^2}{x^3} \, dx=\frac {- 6 a^{2} x^{2} - 8 a b x - 3 b^{2}}{12 x^{4}} \]
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Time = 0.19 (sec) , antiderivative size = 24, normalized size of antiderivative = 0.80 \[ \int \frac {\left (a+\frac {b}{x}\right )^2}{x^3} \, dx=-\frac {6 \, a^{2} x^{2} + 8 \, a b x + 3 \, b^{2}}{12 \, x^{4}} \]
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Time = 0.26 (sec) , antiderivative size = 24, normalized size of antiderivative = 0.80 \[ \int \frac {\left (a+\frac {b}{x}\right )^2}{x^3} \, dx=-\frac {6 \, a^{2} x^{2} + 8 \, a b x + 3 \, b^{2}}{12 \, x^{4}} \]
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Time = 0.04 (sec) , antiderivative size = 24, normalized size of antiderivative = 0.80 \[ \int \frac {\left (a+\frac {b}{x}\right )^2}{x^3} \, dx=-\frac {\frac {a^2\,x^2}{2}+\frac {2\,a\,b\,x}{3}+\frac {b^2}{4}}{x^4} \]
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